-50x^2+125x^2+2x-5=0

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Solution for -50x^2+125x^2+2x-5=0 equation:



-50x^2+125x^2+2x-5=0
We add all the numbers together, and all the variables
75x^2+2x-5=0
a = 75; b = 2; c = -5;
Δ = b2-4ac
Δ = 22-4·75·(-5)
Δ = 1504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1504}=\sqrt{16*94}=\sqrt{16}*\sqrt{94}=4\sqrt{94}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{94}}{2*75}=\frac{-2-4\sqrt{94}}{150} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{94}}{2*75}=\frac{-2+4\sqrt{94}}{150} $

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